Bir veritabanı SQL Server Management Studio 2008 tüm tablolarda bir dize aramak için herhangi bir yolu var mı?

Say john dize aramak istiyorum. Sonuç tabloları ve john içeren kendi satır göstermelidir.

Bu prosedür, belirli bir arama dizesi için: tüm tabloların tüm sütunları aramak için deneyin

CREATE PROC SearchAllTables
(
    @SearchStr nvarchar(100)
)
AS
BEGIN

    CREATE TABLE #Results (ColumnName nvarchar(370), ColumnValue nvarchar(3630))

    SET NOCOUNT ON

    DECLARE @TableName nvarchar(256), @ColumnName nvarchar(128), @SearchStr2 nvarchar(110)
    SET  @TableName = ''
    SET @SearchStr2 = QUOTENAME('%'   @SearchStr   '%','''')

    WHILE @TableName IS NOT NULL

    BEGIN
        SET @ColumnName = ''
        SET @TableName = 
        (
            SELECT MIN(QUOTENAME(TABLE_SCHEMA)   '.'   QUOTENAME(TABLE_NAME))
            FROM     INFORMATION_SCHEMA.TABLES
            WHERE         TABLE_TYPE = 'BASE TABLE'
                AND    QUOTENAME(TABLE_SCHEMA)   '.'   QUOTENAME(TABLE_NAME) > @TableName
                AND    OBJECTPROPERTY(
                        OBJECT_ID(
                            QUOTENAME(TABLE_SCHEMA)   '.'   QUOTENAME(TABLE_NAME)
                             ), 'IsMSShipped'
                               ) = 0
        )

        WHILE (@TableName IS NOT NULL) AND (@ColumnName IS NOT NULL)

        BEGIN
            SET @ColumnName =
            (
                SELECT MIN(QUOTENAME(COLUMN_NAME))
                FROM     INFORMATION_SCHEMA.COLUMNS
                WHERE         TABLE_SCHEMA    = PARSENAME(@TableName, 2)
                    AND    TABLE_NAME    = PARSENAME(@TableName, 1)
                    AND    DATA_TYPE IN ('char', 'varchar', 'nchar', 'nvarchar', 'int', 'decimal')
                    AND    QUOTENAME(COLUMN_NAME) > @ColumnName
            )

            IF @ColumnName IS NOT NULL

            BEGIN
                INSERT INTO #Results
                EXEC
                (
                    'SELECT '''   @TableName   '.'   @ColumnName   ''', LEFT('   @ColumnName   ', 3630) 
                    FROM '   @TableName   ' (NOLOCK) '  
                    ' WHERE '   @ColumnName   ' LIKE '   @SearchStr2
                )
            END
        END    
    END

    SELECT ColumnName, ColumnValue FROM #Results
END